Answer:
± 1/2,±1, ±2,± 5/2, ±4 ,±5 , ±10, ± 20
Explanation:
We can use the rational root theorem to find all the possible roots
2x^3+5x^2-8x-20=0
Let the constant term be called p and the leading term be called q. Then the possible roots are the positive and negative roots of the factors of p/q
p = 20
q = 2
Factors of p: 1,2,4,5,10,20
Factors of q: 1,2
Possible roots
1 ,2,4,5,10,20
± --------------------------------------------------------
1,2
So we get
±1, ±2, ±4 ,±5 , ±10 ± 20 ± 1/2± 2/2,±4/2,± 5/2,± 10/2,± 20/2
Simplifying
±1, ±2, ±4 ,±5 , ±10, ± 20, ± 1/2,± 1,±2,± 5/2,± 5,± 10
Eliminating repeats
±1, ±2, ±4 ,±5 , ±10, ± 20 ,± 1/2,± 5/2
Putting them in numerical order
± 1/2,±1, ±2,± 5/2, ±4 ,±5 , ±10, ± 20