Factor the trinomial below 8x^2-12x-8

asked Aug 19, 2019 152k views

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$8x^2-12x-8=4(2x^2-3x-2)=4(2x^2-4x+x-2)\\\\=4[2x(x-2)+1(x-2)]=4(x-2)(2x+1)\\\\\boxed{ 8x^2-12x-8 =4(x-2)(2x+1)}$

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1 vote

Answer:

4(2x+1)(x-2)

Step-by-step explanation: I just did it

Prashant Borde answered Aug 25, 2019

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