Question

Hurry im despret i need help

Answer 1

The slope-point form of line:

`y-y_1=m(x-x_1)\\\\m=(y_2-y_1)/(x_2-x_1)`

We have the points (-9, 7) and (6, 2). Substitute:

`m=(2-7)/(6-(-9))=(-5)/(6+9)=-(5)/(15)=-(1)/(3)\\\\y-7=-(1)/(3)(x-(-9))\\\\\boxed{y-7=-(1)/(3)(x+9)}`

The slope-intercept form of line:

`y=mx+b`.

We have the slope m:

`y=-(1)/(3)x+b`

Pu the coordinates of the point (6, 2) to the equation:

`2=-(1)/(3)(6)+b`

`2=-2+b` add 2 to both sides

`4=b\to b=4`

`\boxed{y=-(1)/(3)x+4}`