Question

Click the button within the activity, and analyze the relationship between the two reactions that are displayed. The reaction that was on the screen when you started and its derivative demonstrate that the change in enthalpy for a reaction, ΔH, is an extensive property. Using this property, calculate the change in enthalpy for Reaction 2. Reaction 1: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g), ΔH1=â’2043 kJ Reaction 2: 6C3H8(g)+30O2(g)→18CO2(g)+24H2O(g), ΔH2=?

Answer 1

-12 258 kJ

Step-by-step explanation:

Reaction 1: C₃H₈(g)+5O2(g) ⟶ 3CO₂(g)+ 4H₂O(g); ΔH₁ = - 2 043 kJ

Reaction 2: 6C₃H₈(g)+30O2(g) ⟶ 18CO₂(g)+ 24H₂O(g); ΔH₂ = -12 258 kJ

Reaction 2 is Reaction 1 multiplied by 6.

ΔH is an extensive property, so you must also multiply ΔH by 6.