List the first four terms of a geometric sequence with t 1 = 4 and t n = -3t n-1 .

asked Oct 10, 2019 225k views

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$t_1=4\\t_n=-3t_(n-1)\\\\t_2=-3\cdot4=-12\\t_3=-3\cdot(-12)=36\\t_4=-3\cdot36=-108$

Pavlo Ostasha answered Oct 15, 2019

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