Answer:
13.1dm³
Step-by-step explanation:
Given parameters:
Pressure of gas = 880mmHg
760mmHg = 1 atm
880mmHg will give 1.16atm
Temperature = 303k
Mass of gas = 26.9g
Molar mass of CO₂ = 12 + 2(32) = 44g/mol
Number of moles = mass/molar mass = 26.9/44 = 0.61mole
Unknown:
Volume of the sample = ?
Solution:
To solve this problem, we use the ideal gas equation:
PV = nRT
P is the pressure
V is the volume
n is the number of moles
R is the gas constant = 0.082atmdm³mol⁻¹k⁻¹
T is the temperature
V =
=
= 13.1dm³