Question

Find the equation of the line passes through the pints (-2,3) and (1,-4).

Answer 1

m=
`(-7)/(3)`

Explanation:

Given:

(-2,3)(1,-4)

(x₁,y₁)(x₂,y₂)

m=(y₂-x₂)÷(y₁-x₁)

m=(-4 - 3) ÷ (1+2)

m=
`(-7)/(3)`

Answer 2

`3y+7x=-5` is the required equation.

Explanation:

We have been given two points: (-2,3) and (1,-4)

We have a formula to find the equation with two points:

`y-y_1=(y_2-y_1)/(x_2-x_1)\cdot (x-x_1)`

Here, we have:

`x_1=-2,x_2=1,y_1=3,y_2=-4`

On substituting the values in the formula we get:

`y-3=(-4-3)/(1-(-2))\cdot (x-(-2))`

`\Rightarrow y-3=(-7)/(3)\cdot (x+2)`

On further simplification:

`3y-9=-7(x+2)`

`\Rightarrow 3y-9=-7x-14`

After rearranging the terms

`3y+7x=-14+9`

After final simplification we get:

`3y+7x=-5`