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The only solution of the equation x2 + bx + 16 = 0 is x = 4. What is the value of b?

b = –16
b = –8
b = 8
b = 16

User Maktel
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\heartsuit If x = 4 is the Only Solution of the Equation x² + bx + 16 = 0


\heartsuit Then the Value x = 4 should satisfy the Given Equation

⇒ (4)² + b(4) + 16 = 0

⇒ 16 + 4b + 16 = 0

⇒ 4b + 32 = 0

⇒ 4b = -32

⇒ b = -8

User Micki
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