Question

Mary is twice as old as Jane was when Mary was as old as Jane is now. The sum of their ages is 28. What is the age of each girl?

Answer 1

Mary's age is 16.8 years

Jane's age is 11.2 years

Explanation:

Let's assume Jane was x years old

Mary is twice as old as Jane a long time ago

so, Marry's age =2x

difference in age =2x-x=x years

It means that Marry is x year older than Jane

now, we have

Mary was as old as Jane is now

or we can say that

Jane is as old as Mary was

we know that

Mary =2x years

so, Jane age becomes

Jane=2x years

and we have got

As Mary is x years older than Jane

so, Mary's age =2x+x=3x years old now

now, we are given

The sum of their ages is 28

So,

Mary's age + Jane's age =28

`3x+2x=28`

`5x=28`

`x=5.6`

Mary's age is

`=3* 5.6`

`=16.8`

Jane's age is

`=2* 5.6`

`=11.2`