Question

What is the nth term of the geometric sequence 4, 8, 16, 32, ... ?

Answer 1

2^(n+1)

Explanation:

You don't even need to use algebraic methods or the formula for this; it's just common sense. 4=2^2, 8=2^3, 16=2^4.

4 is the term 1

8 is term 2

2=term # (1) + 1 for 4

3 = term # (2) + 1 for 8

And so on

So it is 2 to the power of (term # + 1)

Answer 2

tn = a*2^(n - 1)

Explanation:

a = 4

r = 2

tn= a*2^(n-1)

Try it

t3 = 4*2^(3 -1) Combine the power

t3 = 4 * 2^2 Find 2^2

t3 = 4 * 4 Multiply

t3 = 16 Answer for t3