Question

A stationary block of mass 35 Kg is suspended on a string.What is the tension in the string ?( Neglect the mass of the string)

Answer 1

Tstring = 343.35 [N].

Step-by-step explanation:

Since the block is in equilibrium, we can say that the sum of the forces on the Y-axis or vertical is equal to zero.

∑Fy = 0

`T_(string)-W=0`

where:

Tstring = tension of the string [N]

W = weight of the block [N]

And the weight can be calculated multiplying the mass of the block by the gravity acceleration.

Now replacing:

`T_(string)=m*g\\T_(string)=35*9.81\\T_(string)=343.35[N]`