Question

A 32.8 g sample of gas occupies 22.414 L at STP. What is the molecular weight of this gas?

Answer 1

32.8g/mole

Step-by-step explanation:

Given parameters:

Mass of sample of gas = 32.8g

Volume = 22.4L

Unknown:

Molecular weight = ?

Solution:

To solve this problem we must understand that at rtp;

1 mole of gas occupies a volume of 22.4L

Number of mole of the gas = 1 mole

Now;

Mass = number of moles x molecular weight

molecular weight =
`(mass)/(molecular weight)` =
`(32.8g)/(1mole )` = 32.8g/mole