Question

What does the fundamental theorem of algebra state about the equation 2x^2-4x+16=0?

Answer 1

Answer: (A) degree of 2; 1 ± i√7

Explanation:

Degree of the polynomial designates the number of roots.

x² - 2x + 8

a=1 b=-2 c=8

`x=(-b\pm√(b^2-4ac))/(2a)`

`=(-(-2)\pm√((-2)^2-4(1)(8)))/(2(1))`

`=(2\pm√(4-32))/(2)`

`=(2\pm√(-28))/(2)`

`=(2\pm2i√(7))/(2)`

`=(2(1\pm\\i\sqrt7))/(2)`

= 1 ± i√7