Question

Plz answer its easy math.

Answer 1

`\text{Use}\\\\(a^n)/(a^m)=a^(n-m)\\\\a^(-n)=(1)/(a^n)\\-----------------------\\\\(3^(-8))/(3^(-4))=3^(-8-(-4))=3^(-8+4)=\underbrace{\boxed{3^(-4)}}_{\boxed{B.}}=\underbrace{\boxed{(1)/(3^4)}}_{\boxed{E.}}\\\\Answer:\ \boxed{B.\ and\ E.}`

Answer 2

Greetings!

Answer:

B and E

Explanation:

The rules of indicies states:

`x^(a)` ÷
`x^(b)` =
`x^(a-b)`

So
`3^(-8)` ÷
`3^(-4)` =
`3^(-8 - - 4)` =
`3^(-4)`

So that means B is one of the correct answers.

To find the other correct value, you can divide the two fractions as stated in the question:

`3^(-8)` by
`3^(-4)` =
`(1)/(81)`

81 is equivalent to 3⁴

So that means E is also correct.

Hope this helps!