Question

At 650mm Hg, a gas has a volume of 190L, what is its volume at standard pressure

Answer 1

Answer : The volume of the gas at standard pressure (1 atm) is, 162.45 L

Solution : Given,

Initial pressure of gas = 650 mmHg =
`(650)/(760)=0.855atm`
`(1atm=760mmHg)`

Initial volume of gas = 190 L

Final pressure of gas = 1 atm (standard pressure is 1 atm)

Formula used :
`(P_1)/(P_2)=(V_2)/(V_1)`

where,

`P_1` = initial pressure of gas

`P_2` = final pressure of gas

`V_1` = initial volume of gas

`V_2` = final volume of gas

Now put all the given values in the above formula, we get

`(0.855atm)/(1atm)=(V_2)/(190L)`

By rearranging the terms, we get the final volume of the gas.

`V_2=162.45L`

Therefore, the volume of the gas at standard pressure (1 atm) is, 162.45 L

Answer 2

The volume at standard pressure is 162.5 L

calculation

The volume at Standard pressure (760 mm hg) is calculated using the Boyle's law formula

That is P₁V₁ =P₂V₂

where;

P₁=650 mmHg

V₁= 190 L

P₂ = 760 mm hg

V₂ =? L

make V₂ the formula of the subject by diving both side of equation by P₂

V₂ is therefore = P₁V₁/P₂

= {(650 mmHg x 190 L) / 760 mmHg} =162.5 L