Question

Solve the following problems: Given: ∆AFD, m ∠F = 90° AD = 14, m ∠D = 30° Find: Area of ∆AFD

Answer 1

We have the triangle 30° - 60° - 90°.

The sides are in proportion: 2 : √3 : 1

(look at the picture).

`2a=14` divide both sides by 2

`a=7`

`a\sqrt3=7\sqrt3`

The area of a trinagle AFD:

`A_(\Delta)=(1)/(2)(7)(7\sqrt3)=\boxed{(49\sqrt3)/(2)}`