Answer:
4.3 g
Explanation:
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 60.05 32.00
CH₃CH₂OH + 3O₂ ⟶ 2CO₂ + 3H₂O
Mass/g: 7.0
1. Calculate the moles of O₂
Moles O₂ = 7.0 × 1/32.00
Moles O₂ = 0.219 mol O₂
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2. Calculate the moles of CH₃CH₂OH
The molar ratio is 1 mol CH₃CH₂OH:3 mol O₂
Moles of CH₃CH₂OH = 0.219 × 1/3
Moles of CH₃CH₂OH = 0.0729 mol CH₃CH₂OH
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3. Calculate the mass of CH₃CH₂OH
Mass of CH₃CH₂OH = 0.0729 × 60.05
Mass of CH₃CH₂OH = 4.4 g