Question

2. A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.

a. Calculate the number of moles of C12H22O11 contained in the sample
and record in Table 1. Show your work.

b. Calculate the moles of each element in C12H22O11 and record in Table
1. Show your work.

c. Calculate the number of atoms of each type in C12H22O11 and record in
Table 1. Show your work.

Please show your work and calulation. Thanks

Answer 1

a)
`\text{no of moles}=\frac{\text{given mass}}{\text{Molecular mass}}`

`\text{no of moles of sucrose}=(1.202g)/(342g/mol)=0.0035moles`

b) Moles of carbon in 1 mole of sucrose
`C_(12)H_(22)O_(11)`= 12 moles

Moles of carbon in 0.0035 moles of sucrose
`C_(12)H_(22)O_(11)=(12)/(1)* 0.0035=0.042moles`

Moles of hydrogen in 1 mole of sucrose
`C_(12)H_(22)O_(11)`= 22 moles

Moles of hydrogen in 0.0035 moles of sucrose
`C_(12)H_(22)O_(11)=(22)/(1)* 0.0035=0.077moles`

Moles of oxygen in 1 mole of sucrose
`C_12H_22O_11`= 11 moles

Moles of oxygen in 0.0035 moles of sucrose
`C_(12)H_(22)O_(11)=(11)/(1)* 0.0035=0.042moles`

c) 1 mole of carbon contains
`=6.023* 10^(23)atoms`

0.042 moles of carbon contain
`=(6.023* 10^(23))/(1)* 0.042=0.25* 10^(23)atoms`

1 mole of hydrogen contains
`=6.023* 10^(23)atoms`

0.077 moles of hydrogen contain
`=(6.023* 10^(23))/(1)* 0.077=0.46* 10^(23)atoms`

1 mole of oxygen contains
`=6.023* 10^(23)atoms`

0.042 moles of oxygen contain
`=(6.023* 10^(23))/(1)* 0.042=0.25* 10^(23)atoms`