47.3k views
3 votes
HELP CHECK THIS

The work of a student to solve a set of equations is shown:


Equation A: y = 15 − 2z

Equation B: 2y = 3 − 4z



Step 1: −2(y) = −2(15 − 2z) [Equation A is multiplied by −2.]

2y = 3 − 4z [Equation B]

Step 2: −2y = 15 − 2z [Equation A in Step 1 is simplified.]

2y = 3 − 4z [Equation B]

Step 3: 0 = 18 − 6z [Equations in Step 2 are added.]

Step 4: 6z = 18

Step 5: z = 3



In which step did the student first make an error?

Step1

Step 2

Step 3 <<<<<

Step 4

1 Answer

2 votes
Answer:Step 2 because, the student should not cancel the multiplying constant 2 in the right-hand side but not left-hand side.If the student want to simplify it he should cancel out 2 multiplied in both side.
User Chrisheinze
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories