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4 votes
Someone please help me

Someone please help me-example-1
User Sneaksta
by
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2 Answers

4 votes

Hello from MrBillDoesMath!

Answer:

Choice B is correct

Discussion:

Let y= -2(x+3)^2 - 2 (this is choice B)

The parabola in the diagram passes through the point (-3, -2). Does y? Let's check. Substitute x = -3 in the formula for y:

y = -2 ( -3+3)^2 - 2 = 0 - 2 = -2

so when x = -3, y = -2 and the parabola passes through (-3, -2)

Also note the first term of y is -2(x+3)^2, which is always negative or 0. This means that the parabola opens downward.

You can check the other choices, like I did for choice B, and you will find they fail at least one requirement (either not passing through (-3,-2), or opening the wrong way)

Regards,

MrB

P.S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


User Praneeth Nidarshan
by
9.0k points
6 votes
The answer is B. Find the x-coordinate by setting what is in the parentheses equal to 0 and then it is -2 because the y-coordinate vertex will be the constant at the end.
User Milena Petrovic
by
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