Answer:
First man rate is 115
Second man rate is 50
Explanation:
Let's assume rate of charge of first men is x
rate of charge of second men is y
we are given
the sum of the two rates was 165. per hour
so, we get
![x+y=165](https://img.qammunity.org/2019/formulas/mathematics/middle-school/8ot1pu641i50anfd7pj3jof755wn1v32ih.png)
Two men worked on a car. the first man worked 20 hours and the second man worked 15 hours. Together they charged 3050
so, we get
![20x+15y=3050](https://img.qammunity.org/2019/formulas/mathematics/middle-school/vwmnms1a99q2vkjyaaj0xj06hdhnjmpq5s.png)
we can simplify it
![5(4x+3y)=3050](https://img.qammunity.org/2019/formulas/mathematics/middle-school/kqzw3rvt2shvgskupm0h8sxvso34b1n5hh.png)
![(4x+3y)=610](https://img.qammunity.org/2019/formulas/mathematics/middle-school/e5wdygqf7kp3xh2qv9qldictl2xxxdz47t.png)
so, we got system of equations as
![x+y=165](https://img.qammunity.org/2019/formulas/mathematics/middle-school/8ot1pu641i50anfd7pj3jof755wn1v32ih.png)
![4x+3y=610](https://img.qammunity.org/2019/formulas/mathematics/middle-school/iuq3gafo0p7hou3n208ulzckva0oon12ap.png)
We can solve for y from first equation and plug into second equation
![y=165-x](https://img.qammunity.org/2019/formulas/mathematics/middle-school/fo2wl4ahvbiqwyzfn799dyjm87p3hz3v0g.png)
![4x+3(165-x)=610](https://img.qammunity.org/2019/formulas/mathematics/middle-school/l3e3mtiazkec8xml3jq0y92kog5c724k04.png)
![x+495=610](https://img.qammunity.org/2019/formulas/mathematics/middle-school/qvr7yj06w0bfwo0k3ilda5mqp2wb3gqhhs.png)
![x=115](https://img.qammunity.org/2019/formulas/mathematics/middle-school/f9n60yoxe5qjtzf52vwq4940ejniuo5zl9.png)
now, we can solve for y
![y=165-115](https://img.qammunity.org/2019/formulas/mathematics/middle-school/jro7ofteikkd8desr942mao7657dvk9p86.png)
![y=50](https://img.qammunity.org/2019/formulas/mathematics/college/3fsudvc0e2ddxauonek09p8m8wy6d6xyfa.png)