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3 votes
Gold has a specific heat of 126 J/(kg ! K). A sculptor increased the

temperature of a 0.5 kg block of gold by 10°C. How much energy did
the sculptor add to the gold?

2 Answers

5 votes

Energy Change= Mass X Specific Heat X Temperature Change

126 times .5 = 63.

63 times 10= 630

630 joules

User Asad Shah
by
5.5k points
3 votes

Answer:

630 J

Explanation :

The formula for the heat required is

q = mCΔT

q = 0.5 × 126 × 10

q = 630 J


User Deepali Agarwal
by
5.9k points