Answer:
--3 ±sqrt((-3)^2 -4(4)(-9))
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2(4)
Explanation:
4x^2-5=3x+4
We need to get this in standard form to answer the question
Subtract 3x from each side
4x^2-3x-5=3x-3x+4
4x^2-3x-5=+4
Subtract 4 from each side
4x^2-3x-9 =0
a = 4
b = -3
c = -9
-b ±sqrt(b^2 -4ac)
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2a
--3 ±sqrt((-3)^2 -4(4)(-9))
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2(4)