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Which real numbers are zeroes of the function f(x)=2x^3-x^2-8x+4

Which real numbers are zeroes of the function f(x)=2x^3-x^2-8x+4-example-1
User Viks
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2 Answers

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Answer:

Try math

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Explanation:


User Anice
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4 votes

Answer:

2, -2 and 1/2

Explanation:

As the the first coefficient is 2 and the last number is 4 1/2, 2, -2 seem likely zeros ( By the rational roots theorem).

f(2) = 2*8 - 4 -16 + 4 = 0 so 2 is a zero.

f(-2) = -16 - 4 +16 + 4 = 0 so -2 is a zero

f(1/2) = 2*1/8 - 1/4 - 4 + 4 = 0 so 1/2 is the other zero.

Since the highest degree is 3 the maximum number of zeroes is 3.

User Michael Plakhov
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