Question

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Calculating - A sample it barium nitrate is placed into a jar containing water. The mass of the barium nitrate sample is 27g. Assume the water is at 20°C and that the resulting barium nitrate solution is saturated. What mass of water is present in the jar?

Answer 1

Answer : The mass of of water present in the jar is, 298.79 g

Solution : Given,

Mass of barium nitrate = 27 g

The solubility of barium nitrate at
`20^oC` is 9.02 gram per 100 ml of water.

As, 9.02 gram of barium nitrate present in 100 ml of water

So, 27 gram of barium nitrate present in
`(27g)/(9.02g)* 100ml=299.33ml` of water

The volume of water is 299.33 ml.

As we know that the density of water at
`20^oC` is 0.9982 g/ml

Now we have to calculate the mass of water.

`\text{Mass of water}=\text{Density of water}* \text{Volume of water}`

`\text{Mass of water}=(0.9982g/ml)* (299.33ml)=298.79g`

Therefore, the mass of of water present in the jar is, 298.79 g