Question

In 1991 four English teenagers built an eletric car that could attain a speed of 30.0m/s. Suppose it takes 8.0s for this car to accelerate from 18.0m/s to 30.0m/s. What is the magnitude of the car's acceleration?

Answer 1

a=Δv/Δt=(30.0-18.0)/8.0=12.0/8.0=1.5 m/s²

Answer 2

Acceleration of the car,
`a=1.5\ m/s^2`

Step-by-step explanation:

It is given that,

Initial speed of the car, u = 18 m/s

Final speed of the car, v = 30 m/s

Time taken, t = 8 s

We need to find the acceleration of the car. Let it is given by a. It can be calculated using the first equation of motion.

`v=u+at`

Where

a is the acceleration of the car.

`a=(v-u)/(t)`

`a=(30-18)/(8)`

`a=1.5\ m/s^2`

So, the magnitude of the car's acceleration is
`1.5\ m/s^2`. Hence, this is the required solution.