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What is the value of the remainder if 10x^4 – 6x^3 + 5x^2 – x + 1 is divided by x – 3?

User Zaynyatyi
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1 Answer

3 votes

Answer: 691

Explanation:

There are 3 different ways to find the remainder. I am not sure which method you are supposed to use, so I will solve using all 3 methods.

Long Division:

10x³ + 24x² + 77x + 230

x - 3 ) 10x⁴ - 6x³ + 5x² - x + 1

- (10x⁴ - 30x³) ↓ ↓ ↓

24x³ + 5x² ↓ ↓

- (24x³ - 72x²) ↓ ↓

77x² - x ↓

- (77x² - 231x)

230x + 1

- (230x - 690)

691 ← remainder

Synthetic Division:

x - 3 = 0 ⇒ x = 3

3 | 10 -6 5 -1 1

| ↓ 30 72 231 690

10 24 77 230 691 ← remainder

Remainder Theorem:

f(x) = 10x⁴ - 6x³ + 5x² - x + 1

f(3) = 10(3)⁴ - 6(3)³ + 5(3)² - (3) + 1

= 810 - 162 + 45 - 3 + 1

= 691

User Jeff Standen
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