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The graph of y=x2+11x+24

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Explanation:


y=x^2+11x+24

To graph the above equation , we need to find out the x intercepts

Replace y with 0 and solve for x


0=x^2+11x+24


=(x+8)(x+3)

Set the factors =0 and solve for x

x+8=0 so x=-8

x+3=0 so x=-3

X intercepts are (-8,0) and (-3,0)

Now we find out vertex, we apply formula x=-b/2a

We know a=1 , b= 11


x=(-b)/(2a) =(-11)/(2(1)) = -5.5

Now we plug in x=-5.5 and find out y


y=x^2+11x+24


y=(-5.5)^2+11(-5.5)+24= -6.25

So vertex is (-5.5,-6.25)

We got x intercepts and vertex, the graph is attached below


The graph of y=x2+11x+24-example-1
User David Wurtz
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