Question

5.Calculate the number of moles of 18.0 dm3 of carbon monoxide (CO) at rtp.

Answer 1

0.81mole

Step-by-step explanation:

Given:

Volume of carbon monoxide = 18dm³

Unknown

Number of moles of carbon monoxide = ?

Solution:

To solve this problem;

1 mole of any gas at rtp occupies a volume of 22.4dm³

So;

x mole of carbon monoxide will occupy a volume of 18dm³ at rtp

22.4x = 18

x =
`(18)/(22.4)` = 0.81mole