Question

A baseball with a mass of 0.15 kilograms collides with a bat at a speed of 40 meters/second. The duration of the collision is 8.0 × 10-3 seconds. The ball moves off with a speed of 50 meters/second in the opposite direction. What is the value of the force?

Answer 1

Not sure but dont choose C .

1.3×10^3 Newtons

Step-by-step explanation:

I cant find the answer anywhere but its not C so at least that gets rid of one of the options <3 (its probably not A either bc i feel like thats the closest to the other guys answer and it was rated poorly but choose at ur own risk)

Answer 2

Answer: 1687.5 N

Step-by-step explanation:

From the second law of motion given by Newton, Force is the rate change of momentum.

`F = (dp)/(dt)=\frac {m dv}{dt} = (m (v_f-v_i))/(dt)`

Mass of the baseball, m = 0.15 kg

Initial velocity,
`v_i=-40 m/s` (negative because direction of initial velocity is opposite to the final velocity)

Final velocity,
`v_f=50 m/s`

The duration of collision,
`dt= 8.0 * 10^(-3) s`

Force,
`F = (0.15 kg (50-(-40) m/s))/(8.0 * 10^(-3) s)=1687.5 N`

Hence, the value of force is 1687.5 N.