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2 votes
Which is the equation of a line that has a slope of -2/3 and passes through point (-3,-1)?

2 Answers

4 votes

Answer:


Explanation:

You have to use Point Slope Form:

  • y - Y1 = m (x - X1)
  • m is the slope
  • Y1 & X1 is a point on the line
  • The form allows you to identify the slope & the point on the line

About Problem:

  • Since -2/3 is the slope, it represents m in y - Y1 = m (x - X1) form.
  • -3 represents X1 in y - Y1 = m (x - X1) form
  • -1 represents Y1 in y - Y1 = m (x - X1) form

y - Y1 = m (x - X1)

y - -1 = -2/3 (x - -3) ---- This is in Point Slope Form

If you want to solve it, & put it in Slope Intercept form, it would look like this:

y = mx + b

y = -2/3 - 2 --- This is in Slope intercept Form.... I might've solved it wrong... I'm not sure...


Really really sorry if I'm incorrect...




User Embattled Swag
by
8.0k points
5 votes

Answer: The required equation of the line is
2x+3y+9=0.

Step-by-step explanation: We are given to find the equation of a line that has a slope of
-(2)/(3) and passes through point (-3,-1).

SLOPE-INTERCEPT FORM :

The equation of a line having slope m and passing through the point (a, b) is given by


y-b=m(x-a).

For the given line, we have


m=-(2)/(3),\\\\\\(a,b)=(-3,-1).

Therefore, the equation of the line is given by


y-b=m(x-a)\\\\\Rightarrow y-(-1)=-(2)/(3)(x-(-3))\\\\\\\Rightarrow y+1=-(2)/(3)(x+3)\\\\\Rightarrow 3y+3=-2x-6\\\\\Rightarrow 2x+3y+9=0.

Thus, the required equation of the line is
2x+3y+9=0.

User Newbiiiie
by
8.2k points

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