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Complete the point slope equation of the line through (-2,6) and (1,1)

2 Answers

7 votes

Answer:

y-1 =( -5/3) (x-1)

Explanation:

The point slope equation for a line is

y-y1 = m(x-x1)

where m is the slope and (x1, y1) is a point

We need to determine the slope

The formula for slope is

m = (y2-y1)/(x2-x1)

where (x1,y1) and (x2,y2) are points

m = (1-6)/(1--2)

= (1-6)/(1+2)

=-5/3

The slope is -5/3

Now we can substitute the slope into the equation for a line. We can use either point. I will use (1,1)

y-y1 = m(x-x1)

y-1 =( -5/3) (x-1)

User Eric Steen
by
7.8k points
4 votes

Answer:

y-1 =( -5/3) (x-1)

Explanation:

The point slope equation for a line is

y-y1 = m(x-x1)

where m is the slope and (x1, y1) is a point

We need to determine the slope

The formula for slope is

m = (y2-y1)/(x2-x1)

where (x1,y1) and (x2,y2) are points

m = (1-6)/(1--2)

= (1-6)/(1+2)

=-5/3

The slope is -5/3

Now we can substitute the slope into the equation for a line. We can use either point. I will use (1,1)

y-y1 = m(x-x1)

y-1 =( -5/3) (x-1)

User KingCronus
by
7.3k points