Question

Please help ​What is the equation of a line with a slope of ​ ​ −4 ​ ​ and a point ​ (−2, 5) ​ on the line?

Express the equation in the form of y=mx+b where m is the slope and b is the y-intercept.

Answer 1

all is work is shown and pictured

Answer 2

The point-slope form:

`y-y_1=m(x-x_1)`

We have m = -4 and the point (-2, 5). Substitute:

`y-5=-4(x-(-2))`

`y-5=-4(x+2)` use distributive property

`y-5=(-4)(x)+(-4)(2)`

`y-5=-4x-8` add 5 to both sides

`\boxed{y=-4x-3}`