Question

F(x)=x^3+4x^2+x-6
What are the real zeros

Answer 1

Happy New Year from MrBillDoesMath!

Answer:

1, -2, -3

Discussion:

The real roots of the polynomials are factors of the last term (6) divided by the first term (1). The factors of 6/1 or 6 are 1,2,3, and 6. I found by substitution that x= 1 was a solution, divided the polynomial by x-1, came up with a quadratic (x^2 + 5x + 6), and found the remaining roots via the quadratic formula.

Thank you,

MrB