Question

What is the equation of a line that is parallel to y= 3 5 x−7 y=35x−7 and passes through (15, 8) (15, 8)

Answer 1

The equation of the line parallel to y = 35x - 7 and passing through the point (15, 8) is y = 35x - 517.

Step-by-step explanation:

To find the equation of a line that is parallel to y = 35x - 7 and passes through the point (15, 8), we need to determine the slope of the original line.

Since the given line is in the form y = mx + b, where m is the slope, we can see that the slope of the given line is 35.

Since parallel lines have the same slope, the slope of the line we're looking for is also 35.

Now we can use the point-slope form of a linear equation, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.

Plugging in the values, we have y - 8 = 35(x - 15).

Expanding and simplifying, we get y - 8 = 35x - 525.

Finally, rearranging the equation, we find the equation of the line is y = 35x - 517.

Answer 2

The equation of this line would be y = 35x - 517

Step-by-step explanation:

In order to find this equation we must first find the slope of the original line. The original slope (the coefficient of x) is 35, which means the new slope will also be 35 because parallel lines have the same slope. Now, we can use this slope along with the point in point-slope form to find the equation of the line.

y - y1 = m(x - x1)

y - 8 = 35(x - 15)

y - 8 = 35x - 525

y = 35x - 517