Answer:
1) 4, 7, 12 and 19
Tenth term = 103
2) 2, 8, 18, 32
Tenth term =200
Explanation:
Given the nth term of the sequence
1) f(n)= n²+3
When n = 1
f(1) = 1²+3
f(1) = 4
When n = 2
f(2) = 2²+3
f(2) =4+3
f(2) = 7
When n = 3
f(3) = 3²+3
f(3) = 9+3
f(3)=12
When n =4
f(4) = 4²+3
f(4) = 16+3
f(4) = 19
The first four terms are 4, 7, 12 and 19
f(10)= 10²+3
f(10) = 103
Tenth term is 103
2) f(n) = 2n²
When n = 1
f(1) = 2(1)²
f(1) = 2
When n = 2
f(2) = 2(2)²
f(2) = 2(4)
f(2) = 8
When n= 3
f(3)= 2(3)²
f(3) = 2(9)
f(3) = 18
When n= 4
f(4) = 2(4)²
f(4) = 2(16)
f(4) =32
The first four terms are 2, 8, 18, 32
f(10) = 2(10)²
f(10) =2(100)
f(20) = 200
The tenth term is 200