Question

A worker pushes a crate horizontally across a warehouse floor with a force of 245 N at an angle of 55 degrees below the horizontal. How much of the worker’s force is not used to move the crate? (1 point)

Answer 1

Horizontal component of force is used to find out the work done

`W = Fdcos\theta`

so we can say the work done as

`W = (Fcos\theta)d`

so here the vertical component of force is not used to find out the work done

so here it would be

`F_y = Fsin\theta`

`F_y = 245sin55`

`F_y = 200.7 N`

so 200.7 N is not used to find out work done