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A geostationary satellite has a orbital radius of 4.23*10.7m.
a).calculate it’s speed in orbit

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Answer ;

Note : Satellite completes one orbit in the same time the earth rotates one about its axis

circumference of the orbit = 2 ×π × 4.23×10⁷ (similar to the earth orbital speed

The time of earth/orbit traveled = 23.93 hrs ,

Speed of the orbit = (distance) ÷ (time)

= circumference ÷ time

= (2 ×π × 4.23×10⁷) ÷ 23.93 (1 hr = 3600 sec.)

= 3085.14 m/s

The orbital velocity is 3085.14 m/s



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