Answer:
Length of wire = 50 ft
Explanation:
In the figure below AB is the telephone pole and C is the point on the ground where wire is anchored.
so we have
AB= 45 ft
∠ACB= 64°
Let is assume the length of the wire be x ft
now in Δ ABC
![sin C = (AB)/(AC)](https://img.qammunity.org/2019/formulas/mathematics/college/km5y87svp81mi94z8ufjykhsfmdnehf5br.png)
we can plug AB= 45, ∠C= 64°and AC=x
so we have
°
![=(45)/(x)](https://img.qammunity.org/2019/formulas/mathematics/college/jw51qlisifpcdeb95rjd2yo8x0znib71ex.png)
°
![=45](https://img.qammunity.org/2019/formulas/mathematics/middle-school/cwuzrwolg78tpzw7j5gmfrjcyqoraa5fmk.png)
![x=(45)/(sin(64))](https://img.qammunity.org/2019/formulas/mathematics/college/rhfwbug302cqulbdi6g8cgg78187dn7xdr.png)
now we have sin 64°=0.8988
![x=(45)/(0.8988)](https://img.qammunity.org/2019/formulas/mathematics/college/cbhmi0smr595l0tviooo360tgy1u1n37xq.png)
ft
rounding to nearest foot
x= 50 ft