Question

100.0 mL of 3.8M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer 1

The minimum lethal concentration of sodium cyanide in blood serum is 3.8 × 10⁻⁶ M. In 100.0 mL of this solution, there are 3.8 × 10⁻⁷ moles of NaCN. The mass of the solute in 100.0 mL is 1.8658 × 10⁻⁵ g.

Step-by-step explanation:

The question asks about the concentration of sodium cyanide in blood serum, specifically the minimum lethal concentration.

The concentration is given as 3.8 × 10⁻⁶ M. This means that there are 3.8 × 10-6 moles of NaCN per liter of blood serum.

To calculate the number of moles in 100.0 mL, we can use the formula:

moles = concentration × volume

moles = 3.8 × 10⁻⁶ M × 0.1 L = 3.8 × 10⁻⁷ moles

To calculate the mass of the solute, we can use the formula:

mass = moles × molar mass

The molar mass of NaCN is 49.01 g/mol.

mass = 3.8 × 10⁻⁷ moles × 49.01 g/mol = 1.8658 × 10⁻⁵ g

Therefore the mass is 1.8658 × 10⁻⁵ g

Answer 2

The given question is incomplete. The complete question is:

Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer: The number of moles and the mass of the solute are
`0.38* 10^(-5)` and
`18.62* 10^(-5)g` respectively

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

`Molarity=(n* 1000)/(V_s)`

where,

n = moles of solute

`V_s` = volume of solution in ml

`3.8* 10^(-5)M=(n* 1000)/(100.0)`

`n=0.38* 10^(-5)`

n = moles of
`NaCN` =
`\frac{\text {given mass}}{\text {Molar mass}}`

`0.38* 10^(-5)=(x)/(49g/mol)`

`x=18.62* 10^(-5)g`

Thus the number of moles and the mass of the solute are
`0.38* 10^(-5)` and
`18.62* 10^(-5)g` respectively