Question

What is the difference of (2x+5/x^2-3x)-(3x+5/x^3-9x)-(x+1/x^2-9)

Answer 1

(x+5)(x+2)/x^3-9x

Explanation:

For short if taking on edgen then option A is correct.

Answer 2

The difference of given expressions is
`(x^2+7x+10)/(x^3-9x)`.

Explanation:

The given expression is

`(2x+5)/(x^2-3x)-(3x+5)/(x^3-9x)-(x+1)/(x^2-9)`

Find factors of denominators.

`(2x+5)/(x(x-3))-(3x+5)/(x(x^2-9))-(x+1)/(x^2-9)`

Use
`a^2-b^2=(a-b)(a+b)`

`(2x+5)/(x(x-3))-(3x+5)/(x(x-3)(x+3))-(x+1)/((x-3)(x+3))`

Take
`x(x+3)(x-3)` as LCD.

`((x+3)(2x+5)-(3x+5)-x(x+1))/(x(x+3)(x-3))`

`((2x^2+5x+6x+15)-3x-5-x^2-x)/(x(x^2-3^2))`

`(2x^2+5x+6x+15-4x-5-x^2)/(x(x^2-9))`

`(x^2+7x+10)/(x^3-9x)`

Therefore the difference of given expressions is
`(x^2+7x+10)/(x^3-9x)`.