Question

A vessel contains 18.06*10^23 molecules of Ammonia gas at 25oc. Calculate the number of atoms present

Answer 1

Answer:
`72.3* 10^(23)` atoms

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance contains avogadro's number
`6.023* 10^(23)` of particles and weighs equal to the molecular mass.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given molecules}}{\text {avogadro's number}}`

`[tex]\text{Number of moles of ammonia}=(18.06* 10^(23))/(6.023* 10^(23))=3moles`

As 1 mole of
`NH_3` contains =
`4* 6.023* 10^(23)` atoms

3 moles of
`NH_3` contains =
`(4* 6.023* 10^(23))/(1)* 3=72.3* 10^(23)` atoms

Thus
`72.3* 10^(23)` atoms are present