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What is the force of friction between the dragsters tires and the track if the dragster mass is 300kg and the coefficient of the friction force is 0.8

User Tony Wall
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2 Answers

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Final answer:

The force of friction between the dragster's tires and the track is 2352 newtons, calculated using the formula F=μN with the given mass of 300kg and the coefficient of friction 0.8.

Step-by-step explanation:

The force of friction between the dragster's tires and the track can be calculated using the formula F=μN, where F is the frictional force, μ is the coefficient of friction, and N is the normal force. In this case, the normal force is equal to the weight of the dragster, which is the mass (m) times the acceleration due to gravity (g), N = mg. Given that the mass (m) is 300kg and the coefficient of friction (μ) is 0.8, the force of friction can be calculated as:

F = μ × mg = 0.8 × 300kg × 9.8m/s² = 2352N

Therefore, the force of friction is 2352 newtons (N).

User LowCool
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Ff=μN=μmg=0.8*300*10=2400 N

User Yuu Woods
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