Question

A line passes through the point (-9,3) and has a slope of -2/3?

Write an equation in point slope for this line.

Answer 1

The point-slope form:

`y-y_1=m(x-x_1)`

We have the slope m = -2/3 and the point (-9, 3). Substitute:

`y-3=-(2)/(3)(x-(-9))`

`y-3=-(2)/(3)(x+9)` use distributive property

`y-3=-(2)/(3)x-(2)/(3)\cdot9`

`y-3=-(2)/(3)x-(2)(3)`

`y-3=-(2)/(3)x-6` add 3 to both sides

`\boxed{y=-(2)/(3)x-3}`