Question

How many moles of 02 can be prepared from 6.75 moles of KCIO3 ?

Answer 1

The equation for this question could be
`2KClO_(3)`→
`2KCl+3O_(2)` .

so for 6.75 moles of
`KClO_(3)` *3 moles of O_{2}/2 moles of
`KClO_(3)`

= 10.125