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Can someone help me with these please?

Can someone help me with these please?-example-1
User Quux
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Point-slope form: y-y1 = m(x-x1)

Standard form: ax + by = c

Slope-intercept form: y = mx+b


Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.


To create point-slope form, we need to get one point from the graph. Let's use (3,0).


y = -(4)/(3)(x-3)


To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.


y = -(4)/(3)x + 4


To get standard form, solve the equation in terms of C.


Point-slope form: y = -4/3(x-3)

Slope-intercept form: y = -4/3x + 4

Standard form: 4/3x + y = 4



User Kristian Hanekamp
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