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What is the general equation of a circle centered at the origin?

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Answer:


It is x2+y2−169=0.

Step-by-step explanation:


The circle you are looking fore is composed by all the points with a distance from the origin of 13/ The distance of a point from the center is


d=√x2+y2 and this distance has to be 13, so


13=√x2+y2 and to obtain the equation we can do the square


132=x2+y2 and the final equation is


x2+y2−169=0.



User David Kirkland
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