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Find the equation of the circle with center at (3, 2) and through the point (5, 4).

2 Answers

3 votes
(x - 3)² + (y - 2)² = 8
User Jack Murphy
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6 votes

Answer:

(x - 3)² + (y - 2)² = 8

Explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

The radius is the distance from the centre to a point on the circle

To find r use the distance formula

r = √(x₂ - x₁)² + (y₂ - y₁)²

with (x₁, y₁ ) = (3, 2) and (x₂, y₂ ) = (5, 4)

r =
√((5-3)^2+(4-2)^2) =
√(4+4) =
√(8)

(x - 3)² + (y - 2)² = (
√(8)

(x - 3)² + (y - 2)² = 8 ← equation of circle


User Adenike
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8.2k points