Question

1. A candy bowl in Blake's kitchen has 12 red candies, 15 blue candies, 6 green candies, 11 yellow candies and 16 orange candies. Blake randomly chooses one candy from the bowl without looking. What is the probability that he will choose a red, green or orange candy? Express your probability answer as a fraction, decimal and percent

Answer 1

The probability that Blake will choose a red, green or orange candy
`(17)/(30)` or
`0.57` or
`56.67\%`.

Explanation:

Number of red candies
`=12`.

Number of blue candies
`=15`.

Number of green candies
`=6`.

Number of yellow candies
`=11`.

Number of orange candies
`=16`.

Total number of candies
`=12+15+6+11+16=60`.

Probability of an event
`\textrm{E}`,
`\textrm{P}(\textrm{E})=\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}`

Number of red, green or orange candies
`=12+6+16=34`.

So, the probability that he will choose a red, green or orange candy
`=(34)/(60) =(17)/(30)` or
`0.57` or
`56.67\%`.