Answer:
19.84 m
Step-by-step explanation:
The following data were obtained from the question:
Speed of sound (v) = 345 m/s
Time (t) = 0.115 s
Distance (x) =?
The distance of the object away can be obtained as follow:
v = 2x / t
345 = 2x / 0.115
Cross multiply
345 × 0.115 = 2x
39.675 = 2x
Divide both side by 2
x = 39.675 / 2
x = 19.84 m
Thus, the object is 19.84 m away from the camera.